Distance de vol entre Aéroport International Netaji Subhas Chandra Bose et Aéroport international de Cleveland-Hopkins

À propos de cette route

The direct flight distance between Aéroport International Netaji Subhas Chandra Bose (Calcutta) (CCU) and Aéroport international de Cleveland-Hopkins (Cleveland) (CLE) is approximately 12,822 kilometers (7,967 miles). An average commercial jet flying non-stop at a cruising speed of 900 km/h requires about 14h 45min of total flight time, including 30 minutes for taxiing, takeoff, and landing procedures. Travelers flying this route will cross time zones, experiencing an official time difference of N/A between the departure and arrival locations. Estimated carbon emissions for an economy class passenger on this route are roughly 1,475 kg of CO2. Use our interactive flight range map and route calculator to plan connections, compare airlines, and analyze flight paths between CCU and CLE.