Distancia de vuelo entre Aeropuerto Internacional de Cleveland-Hopkins y SAN

Sobre esta ruta

The direct flight distance between Aeropuerto Internacional de Cleveland-Hopkins (Cleveland) (CLE) and SAN (San Diego) (SAN) is approximately 3,255 kilometers (2,022 miles). An average commercial jet flying non-stop at a cruising speed of 900 km/h requires about 4h 7min of total flight time, including 30 minutes for taxiing, takeoff, and landing procedures. Travelers flying this route will cross time zones, experiencing an official time difference of N/A between the departure and arrival locations. Estimated carbon emissions for an economy class passenger on this route are roughly 374 kg of CO2. Use our interactive flight range map and route calculator to plan connections, compare airlines, and analyze flight paths between CLE and SAN.